Optimal. Leaf size=288 \[ \frac{2 b e m n \text{PolyLog}\left (2,-\frac{f x}{e}\right ) \left (a+b \log \left (c x^n\right )\right )}{f}-\frac{2 b^2 e m n^2 \text{PolyLog}\left (2,-\frac{f x}{e}\right )}{f}-\frac{2 b^2 e m n^2 \text{PolyLog}\left (3,-\frac{f x}{e}\right )}{f}+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )+\frac{e m \log \left (\frac{f x}{e}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{f}-m x \left (a+b \log \left (c x^n\right )\right )^2-2 a b n x \log \left (d (e+f x)^m\right )-\frac{2 b e m n (a-b n) \log (e+f x)}{f}+2 a b m n x+2 b m n x (a-b n)-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )-\frac{2 b^2 e m n \log \left (c x^n\right ) \log \left (\frac{f x}{e}+1\right )}{f}+4 b^2 m n x \log \left (c x^n\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-4 b^2 m n^2 x \]
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Rubi [A] time = 0.35215, antiderivative size = 288, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 11, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.478, Rules used = {2296, 2295, 2371, 6, 43, 2351, 2317, 2391, 2353, 2374, 6589} \[ \frac{2 b e m n \text{PolyLog}\left (2,-\frac{f x}{e}\right ) \left (a+b \log \left (c x^n\right )\right )}{f}-\frac{2 b^2 e m n^2 \text{PolyLog}\left (2,-\frac{f x}{e}\right )}{f}-\frac{2 b^2 e m n^2 \text{PolyLog}\left (3,-\frac{f x}{e}\right )}{f}+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )+\frac{e m \log \left (\frac{f x}{e}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{f}-m x \left (a+b \log \left (c x^n\right )\right )^2-2 a b n x \log \left (d (e+f x)^m\right )-\frac{2 b e m n (a-b n) \log (e+f x)}{f}+2 a b m n x+2 b m n x (a-b n)-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )-\frac{2 b^2 e m n \log \left (c x^n\right ) \log \left (\frac{f x}{e}+1\right )}{f}+4 b^2 m n x \log \left (c x^n\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-4 b^2 m n^2 x \]
Antiderivative was successfully verified.
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Rule 2296
Rule 2295
Rule 2371
Rule 6
Rule 43
Rule 2351
Rule 2317
Rule 2391
Rule 2353
Rule 2374
Rule 6589
Rubi steps
\begin{align*} \int \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right ) \, dx &=-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-(f m) \int \left (-\frac{2 a b n x}{e+f x}+\frac{2 b^2 n^2 x}{e+f x}-\frac{2 b^2 n x \log \left (c x^n\right )}{e+f x}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{e+f x}\right ) \, dx\\ &=-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-(f m) \int \left (\frac{\left (-2 a b n+2 b^2 n^2\right ) x}{e+f x}-\frac{2 b^2 n x \log \left (c x^n\right )}{e+f x}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{e+f x}\right ) \, dx\\ &=-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-(f m) \int \frac{x \left (a+b \log \left (c x^n\right )\right )^2}{e+f x} \, dx+\left (2 b^2 f m n\right ) \int \frac{x \log \left (c x^n\right )}{e+f x} \, dx+(2 b f m n (a-b n)) \int \frac{x}{e+f x} \, dx\\ &=-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-(f m) \int \left (\frac{\left (a+b \log \left (c x^n\right )\right )^2}{f}-\frac{e \left (a+b \log \left (c x^n\right )\right )^2}{f (e+f x)}\right ) \, dx+\left (2 b^2 f m n\right ) \int \left (\frac{\log \left (c x^n\right )}{f}-\frac{e \log \left (c x^n\right )}{f (e+f x)}\right ) \, dx+(2 b f m n (a-b n)) \int \left (\frac{1}{f}-\frac{e}{f (e+f x)}\right ) \, dx\\ &=2 b m n (a-b n) x-\frac{2 b e m n (a-b n) \log (e+f x)}{f}-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-m \int \left (a+b \log \left (c x^n\right )\right )^2 \, dx+(e m) \int \frac{\left (a+b \log \left (c x^n\right )\right )^2}{e+f x} \, dx+\left (2 b^2 m n\right ) \int \log \left (c x^n\right ) \, dx-\left (2 b^2 e m n\right ) \int \frac{\log \left (c x^n\right )}{e+f x} \, dx\\ &=-2 b^2 m n^2 x+2 b m n (a-b n) x+2 b^2 m n x \log \left (c x^n\right )-m x \left (a+b \log \left (c x^n\right )\right )^2-\frac{2 b e m n (a-b n) \log (e+f x)}{f}-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-\frac{2 b^2 e m n \log \left (c x^n\right ) \log \left (1+\frac{f x}{e}\right )}{f}+\frac{e m \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac{f x}{e}\right )}{f}+(2 b m n) \int \left (a+b \log \left (c x^n\right )\right ) \, dx-\frac{(2 b e m n) \int \frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{f x}{e}\right )}{x} \, dx}{f}+\frac{\left (2 b^2 e m n^2\right ) \int \frac{\log \left (1+\frac{f x}{e}\right )}{x} \, dx}{f}\\ &=2 a b m n x-2 b^2 m n^2 x+2 b m n (a-b n) x+2 b^2 m n x \log \left (c x^n\right )-m x \left (a+b \log \left (c x^n\right )\right )^2-\frac{2 b e m n (a-b n) \log (e+f x)}{f}-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-\frac{2 b^2 e m n \log \left (c x^n\right ) \log \left (1+\frac{f x}{e}\right )}{f}+\frac{e m \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac{f x}{e}\right )}{f}-\frac{2 b^2 e m n^2 \text{Li}_2\left (-\frac{f x}{e}\right )}{f}+\frac{2 b e m n \left (a+b \log \left (c x^n\right )\right ) \text{Li}_2\left (-\frac{f x}{e}\right )}{f}+\left (2 b^2 m n\right ) \int \log \left (c x^n\right ) \, dx-\frac{\left (2 b^2 e m n^2\right ) \int \frac{\text{Li}_2\left (-\frac{f x}{e}\right )}{x} \, dx}{f}\\ &=2 a b m n x-4 b^2 m n^2 x+2 b m n (a-b n) x+4 b^2 m n x \log \left (c x^n\right )-m x \left (a+b \log \left (c x^n\right )\right )^2-\frac{2 b e m n (a-b n) \log (e+f x)}{f}-2 a b n x \log \left (d (e+f x)^m\right )+2 b^2 n^2 x \log \left (d (e+f x)^m\right )-2 b^2 n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+x \left (a+b \log \left (c x^n\right )\right )^2 \log \left (d (e+f x)^m\right )-\frac{2 b^2 e m n \log \left (c x^n\right ) \log \left (1+\frac{f x}{e}\right )}{f}+\frac{e m \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac{f x}{e}\right )}{f}-\frac{2 b^2 e m n^2 \text{Li}_2\left (-\frac{f x}{e}\right )}{f}+\frac{2 b e m n \left (a+b \log \left (c x^n\right )\right ) \text{Li}_2\left (-\frac{f x}{e}\right )}{f}-\frac{2 b^2 e m n^2 \text{Li}_3\left (-\frac{f x}{e}\right )}{f}\\ \end{align*}
Mathematica [A] time = 0.195642, size = 507, normalized size = 1.76 \[ \frac{2 b e m n \text{PolyLog}\left (2,-\frac{f x}{e}\right ) \left (a+b \log \left (c x^n\right )-b n\right )-2 b^2 e m n^2 \text{PolyLog}\left (3,-\frac{f x}{e}\right )+a^2 f x \log \left (d (e+f x)^m\right )+a^2 e m \log (e+f x)+a^2 (-f) m x+2 a b f x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+2 a b e m \log \left (c x^n\right ) \log (e+f x)-2 a b f m x \log \left (c x^n\right )-2 a b f n x \log \left (d (e+f x)^m\right )-2 a b e m n \log (e+f x)-2 a b e m n \log (x) \log (e+f x)+2 a b e m n \log (x) \log \left (\frac{f x}{e}+1\right )+4 a b f m n x+b^2 f x \log ^2\left (c x^n\right ) \log \left (d (e+f x)^m\right )-2 b^2 f n x \log \left (c x^n\right ) \log \left (d (e+f x)^m\right )+b^2 e m \log ^2\left (c x^n\right ) \log (e+f x)-2 b^2 e m n \log \left (c x^n\right ) \log (e+f x)-2 b^2 e m n \log (x) \log \left (c x^n\right ) \log (e+f x)+2 b^2 e m n \log (x) \log \left (c x^n\right ) \log \left (\frac{f x}{e}+1\right )-b^2 f m x \log ^2\left (c x^n\right )+4 b^2 f m n x \log \left (c x^n\right )+2 b^2 f n^2 x \log \left (d (e+f x)^m\right )+b^2 e m n^2 \log ^2(x) \log (e+f x)-b^2 e m n^2 \log ^2(x) \log \left (\frac{f x}{e}+1\right )+2 b^2 e m n^2 \log (e+f x)+2 b^2 e m n^2 \log (x) \log (e+f x)-2 b^2 e m n^2 \log (x) \log \left (\frac{f x}{e}+1\right )-6 b^2 f m n^2 x}{f} \]
Antiderivative was successfully verified.
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Maple [F] time = 1.948, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) ^{2}\ln \left ( d \left ( fx+e \right ) ^{m} \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{{\left (b^{2} e m \log \left (f x + e\right ) -{\left (f m - f \log \left (d\right )\right )} b^{2} x\right )} \log \left (x^{n}\right )^{2} +{\left (b^{2} f x \log \left (x^{n}\right )^{2} - 2 \,{\left ({\left (f n - f \log \left (c\right )\right )} b^{2} - a b f\right )} x \log \left (x^{n}\right ) -{\left (2 \,{\left (f n - f \log \left (c\right )\right )} a b -{\left (2 \, f n^{2} - 2 \, f n \log \left (c\right ) + f \log \left (c\right )^{2}\right )} b^{2} - a^{2} f\right )} x\right )} \log \left ({\left (f x + e\right )}^{m}\right )}{f} - \int \frac{{\left ({\left (f^{2} m - f^{2} \log \left (d\right )\right )} a^{2} - 2 \,{\left (f^{2} m n -{\left (f^{2} m - f^{2} \log \left (d\right )\right )} \log \left (c\right )\right )} a b +{\left (2 \, f^{2} m n^{2} - 2 \, f^{2} m n \log \left (c\right ) +{\left (f^{2} m - f^{2} \log \left (d\right )\right )} \log \left (c\right )^{2}\right )} b^{2}\right )} x^{2} -{\left (b^{2} e f \log \left (c\right )^{2} \log \left (d\right ) + 2 \, a b e f \log \left (c\right ) \log \left (d\right ) + a^{2} e f \log \left (d\right )\right )} x + 2 \,{\left ({\left ({\left (f^{2} m - f^{2} \log \left (d\right )\right )} a b -{\left (2 \, f^{2} m n - f^{2} n \log \left (d\right ) -{\left (f^{2} m - f^{2} \log \left (d\right )\right )} \log \left (c\right )\right )} b^{2}\right )} x^{2} -{\left (a b e f \log \left (d\right ) +{\left (e f m n - e f n \log \left (d\right ) + e f \log \left (c\right ) \log \left (d\right )\right )} b^{2}\right )} x +{\left (b^{2} e f m n x + b^{2} e^{2} m n\right )} \log \left (f x + e\right )\right )} \log \left (x^{n}\right )}{f^{2} x^{2} + e f x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b^{2} \log \left (c x^{n}\right )^{2} + 2 \, a b \log \left (c x^{n}\right ) + a^{2}\right )} \log \left ({\left (f x + e\right )}^{m} d\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \log \left (c x^{n}\right ) + a\right )}^{2} \log \left ({\left (f x + e\right )}^{m} d\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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